Fixing the issue in assumption of OLS step by step or one by one
Recent newsHi, I want to raise the issue related to know whether your OLS is ok or not.
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What is normality in regression?
Normality means that the residual in regression is distributed normally, meaning that there is a huge amount of data in the middle and a couple of tails on both the left and right.
Many researchers believe that multiple regression requires normality. This is not the case. Normality of residuals is only required for valid hypothesis testing; that is, the normality assumption assures that the p-values for the t-tests and F-test will be valid. Normality is not required to obtain unbiased estimates of the regression coefficients. OLS regression merely requires that the residuals (errors) be identically and independently distributed.
Furthermore, there is no assumption or requirement that the predictor variables be normally distributed. If this were the case, then we would not be able to use dummy-coded variables in our models.
After we run a regression analysis, we can use the predict command to create residuals and then use commands such as kdensity, qnorm and pnorm to check the normality of the residuals.
Let’s use the elemapi2 data file we saw in Chapter 1 for these analyses. Let’s predict academic performance (api00) from the percent receiving free meals (meals), percent of English language learners (ell), and percent of teachers with emergency credentials (emer).
use https://stats.idre.ucla.edu/stat/stata/webbooks/reg/elemapi2 regress api00 meals ell emer Source | SS df MS Number of obs = 400 ---------+------------------------------ F( 3, 396) = 673.00 Model | 6749782.75 3 2249927.58 Prob > F = 0.0000 Residual | 1323889.25 396 3343.15467 R-squared = 0.8360 ---------+------------------------------ Adj R-squared = 0.8348 Total | 8073672.00 399 20234.7669 Root MSE = 57.82 ------------------------------------------------------------------------------ api00 | Coef. Std. Err. t P>|t| [95% Conf. Interval] ---------+-------------------------------------------------------------------- meals | -3.159189 .1497371 -21.098 0.000 -3.453568 -2.864809 ell | -.9098732 .1846442 -4.928 0.000 -1.272878 -.5468678 emer | -1.573496 .293112 -5.368 0.000 -2.149746 -.9972456 _cons | 886.7033 6.25976 141.651 0.000 874.3967 899.0098 ------------------------------------------------------------------------------
We then use the predict command to generate residuals.
predict r, resid
Below we use the kdensity command to produce a kernel density plot with the normal option requesting that a normal density be overlaid on the plot. kdensity stands for kernel density estimate. It can be considered a histogram with narrow bins and a moving average.
kdensity r, normal
The pnorm command graphs a standardized normal probability (P-P) plot while qnorm plots the quantiles of a variable against the quantiles of a normal distribution. pnorm is sensitive to non-normality in the middle range of data and qnorm is sensitive to non-normality near the tails. As you see below, the results from pnorm show no indications of non-normality, while the qnorm command shows a slight deviation from normal at the upper tail, as can be seen in the kdensity above. Nevertheless, this seems to be a minor and trivial deviation from normality. We can accept that the residuals are close to a normal distribution.
pnorm r qnorm r
There are also numerical tests for testing normality. One of the tests is written by Lawrence C. Hamilton, Dept. of Sociology, Univ. of New Hampshire, called iqr. You can get this program from Stata by typing search iqr (see How I can used the search command to search for programs and get additional help? for more information about using search).
iqr stands for inter-quartile range and assumes the symmetry of the distribution. Severe outliers consist of those points that are either 3 inter-quartile ranges below the first quartile or 3 inter-quartile ranges above the third quartile. Any severe outliers should be sufficient evidence to reject normality at a 5% significance level. Mild outliers are common in samples of any size. In our case, we don’t have any severe outliers, and the distribution seems pretty symmetric. The residuals have an approximately normal distribution.
iqr r mean= 7.4e-08 std.dev.= 57.6 (n= 400) median= -3.657 pseudo std.dev.= 56.69 (IQR= 76.47) 10 trim= -1.083 low high ------------------- inner fences -154.7 151.2 # mild outliers 1 5 % mild outliers 0.25% 1.25% outer fences -269.4 265.9 # severe outliers 0 0 % severe outliers 0.00% 0.00%
Another test available is the swilk test which performs the Shapiro-Wilk W test for normality. The p-value is based on the assumption that the distribution is normal. In our example, it is very large (.51), indicating that we cannot reject that r is normally distributed.
swilk r Shapiro-Wilk W test for normal data Variable | Obs W V z Pr > z ---------+------------------------------------------------- r | 400 0.99641 0.989 -0.025 0.51006
Hi, I want to raise the issue related to know whether your OLS is ok or not.
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